Use a sliding window with two pointers (left and right) and a hash set. Advance the right pointer to expand the window, and if a character repeats, increment the left pointer to shrink the window until all characters are unique.
class Solution:
def lengthOfLongestSubstring(self, s: str) -> int:
char_set = set()
left = 0
max_len = 0
for right in range(len(s)):
while s[right] in char_set:
char_set.remove(s[left])
left += 1
char_set.add(s[right])
max_len = max(max_len, right - left + 1)
return max_len
class Solution {
public int lengthOfLongestSubstring(String s) {
Set set = new HashSet<>();
int left = 0, maxLen = 0;
for (int right = 0; right < s.length(); right++) {
while (set.contains(s.charAt(right))) {
set.remove(s.charAt(left++));
}
set.add(s.charAt(right));
maxLen = Math.max(maxLen, right - left + 1);
}
return maxLen;
}
}